28x-10-19x=3(3x-4)+2

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Solution for 28x-10-19x=3(3x-4)+2 equation: 



28x-10-19x=3(3x-4)+2

We move all terms to the left:

28x-10-19x-(3(3x-4)+2)=0

We add all the numbers together, and all the variables

9x-(3(3x-4)+2)-10=0



We calculate terms in parentheses: -(3(3x-4)+2), so:

3(3x-4)+2

We multiply parentheses

9x-12+2

We add all the numbers together, and all the variables

9x-10

Back to the equation:

-(9x-10)



We get rid of parentheses

9x-9x+10-10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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