28x-11-16x=3(4x-5)+4

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Solution for 28x-11-16x=3(4x-5)+4 equation: 



28x-11-16x=3(4x-5)+4

We move all terms to the left:

28x-11-16x-(3(4x-5)+4)=0

We add all the numbers together, and all the variables

12x-(3(4x-5)+4)-11=0



We calculate terms in parentheses: -(3(4x-5)+4), so:

3(4x-5)+4

We multiply parentheses

12x-15+4

We add all the numbers together, and all the variables

12x-11

Back to the equation:

-(12x-11)



We get rid of parentheses

12x-12x+11-11=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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