28x-19-19x=3(3x-4)+2

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Solution for 28x-19-19x=3(3x-4)+2 equation:



28x-19-19x=3(3x-4)+2
We move all terms to the left:
28x-19-19x-(3(3x-4)+2)=0
We add all the numbers together, and all the variables
9x-(3(3x-4)+2)-19=0
We calculate terms in parentheses: -(3(3x-4)+2), so:
3(3x-4)+2
We multiply parentheses
9x-12+2
We add all the numbers together, and all the variables
9x-10
Back to the equation:
-(9x-10)
We get rid of parentheses
9x-9x+10-19=0
We add all the numbers together, and all the variables
-9!=0
There is no solution for this equation

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