28x-2(4x-1)=3(1+3x)+12

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Solution for 28x-2(4x-1)=3(1+3x)+12 equation: 



28x-2(4x-1)=3(1+3x)+12

We move all terms to the left:

28x-2(4x-1)-(3(1+3x)+12)=0

We add all the numbers together, and all the variables

28x-2(4x-1)-(3(3x+1)+12)=0

We multiply parentheses

28x-8x-(3(3x+1)+12)+2=0



We calculate terms in parentheses: -(3(3x+1)+12), so:

3(3x+1)+12

We multiply parentheses

9x+3+12

We add all the numbers together, and all the variables

9x+15

Back to the equation:

-(9x+15)



We add all the numbers together, and all the variables

20x-(9x+15)+2=0

We get rid of parentheses

20x-9x-15+2=0

We add all the numbers together, and all the variables

11x-13=0

We move all terms containing x to the left, all other terms to the right

11x=13

x=13/11

x=1+2/11

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