28x-3=(19x+12)+6x

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Solution for 28x-3=(19x+12)+6x equation: 



28x-3=(19x+12)+6x

We move all terms to the left:

28x-3-((19x+12)+6x)=0



We calculate terms in parentheses: -((19x+12)+6x), so:

(19x+12)+6x

We add all the numbers together, and all the variables

6x+(19x+12)

We get rid of parentheses

6x+19x+12

We add all the numbers together, and all the variables

25x+12

Back to the equation:

-(25x+12)



We get rid of parentheses

28x-25x-12-3=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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