28x-5=2+3(x+3)

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Solution for 28x-5=2+3(x+3) equation: 



28x-5=2+3(x+3)

We move all terms to the left:

28x-5-(2+3(x+3))=0



We calculate terms in parentheses: -(2+3(x+3)), so:

2+3(x+3)

determiningTheFunctionDomain
3(x+3)+2

We multiply parentheses

3x+9+2

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We get rid of parentheses

28x-3x-11-5=0

We add all the numbers together, and all the variables

25x-16=0

We move all terms containing x to the left, all other terms to the right

25x=16

x=16/25

x=16/25

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