28x-8(2x-4)=10(4x+2)+6

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Solution for 28x-8(2x-4)=10(4x+2)+6 equation:



28x-8(2x-4)=10(4x+2)+6
We move all terms to the left:
28x-8(2x-4)-(10(4x+2)+6)=0
We multiply parentheses
28x-16x-(10(4x+2)+6)+32=0
We calculate terms in parentheses: -(10(4x+2)+6), so:
10(4x+2)+6
We multiply parentheses
40x+20+6
We add all the numbers together, and all the variables
40x+26
Back to the equation:
-(40x+26)
We add all the numbers together, and all the variables
12x-(40x+26)+32=0
We get rid of parentheses
12x-40x-26+32=0
We add all the numbers together, and all the variables
-28x+6=0
We move all terms containing x to the left, all other terms to the right
-28x=-6
x=-6/-28
x=3/14

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