If it's not what You are looking for type in the equation solver your own equation and let us solve it.
28x^2+39x+5=0
a = 28; b = 39; c = +5;
Δ = b2-4ac
Δ = 392-4·28·5
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-31}{2*28}=\frac{-70}{56} =-1+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+31}{2*28}=\frac{-8}{56} =-1/7 $
| 2x+16=-3x+34-x | | -3x2+36x-108=0 | | 2x-8x+23=4x+33 | | 17x-(7x-9)=39 | | 7x+2x-6x=19+2 | | 101996+8.5x=20658+25.25x | | -5a+4+6a=12-25 | | .12x=26+.08x | | 9w-33=2(w+8) | | 2^(12-4x)=16 | | 67.96+.13x=53.96+.15x | | (4-x)/5=(x+4)/2 | | 9+0.14x=23+.10x | | 7a^2-42=0 | | 64d²-1=0 | | 34-5x=6x+1 | | 64d-1=0 | | 0=-3t^+12t+36 | | 5x-2x+1=x-11 | | 28x^2+17x-6=0 | | 1-4(2x+3)=5(x-2)-3(x+1) | | 3x²-18=0 | | 6x-28=-2(x+2) | | 10/3=4/u-5 | | 5x=3(2x-8)=9 | | 9x^2-45x+52=0 | | -3x-8=1- | | 3x+4x-22=66x | | X-36=-9-2x | | 100-21+43k=74k | | x*0.8=63 | | 25y+14=5y |