28x2-32x+1=0

Solution for 28x2-32x+1=0 equation:

28x^2-32x+1=0

a = 28; b = -32; c = +1;
Δ = b2-4ac
Δ = -322-4·28·1
Δ = 912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{912}=\sqrt{16*57}=\sqrt{16}*\sqrt{57}=4\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{57}}{2*28}=\frac{32-4\sqrt{57}}{56}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{57}}{2*28}=\frac{32+4\sqrt{57}}{56}
$