28y+13=25y+26-12

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Solution for 28y+13=25y+26-12 equation:



28y+13=25y+26-12
We move all terms to the left:
28y+13-(25y+26-12)=0
We add all the numbers together, and all the variables
28y-(25y+14)+13=0
We get rid of parentheses
28y-25y-14+13=0
We add all the numbers together, and all the variables
3y-1=0
We move all terms containing y to the left, all other terms to the right
3y=1
y=1/3
y=1/3

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