28y-6(3y-5)=49

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Solution for 28y-6(3y-5)=49 equation: 



28y-6(3y-5)=49

We move all terms to the left:

28y-6(3y-5)-(49)=0

We multiply parentheses

28y-18y+30-49=0

We add all the numbers together, and all the variables

10y-19=0

We move all terms containing y to the left, all other terms to the right

10y=19

y=19/10

y=1+9/10

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