28y=3(9y-4)

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Solution for 28y=3(9y-4) equation: 



28y=3(9y-4)

We move all terms to the left:

28y-(3(9y-4))=0



We calculate terms in parentheses: -(3(9y-4)), so:

3(9y-4)

We multiply parentheses

27y-12

Back to the equation:

-(27y-12)



We get rid of parentheses

28y-27y+12=0

We add all the numbers together, and all the variables

y+12=0

We move all terms containing y to the left, all other terms to the right

y=-12

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