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29(2t+4)=3/4(24-8t)
We move all terms to the left:
29(2t+4)-(3/4(24-8t))=0
Domain of the equation: 4(24-8t))!=0We add all the numbers together, and all the variables
t∈R
29(2t+4)-(3/4(-8t+24))=0
We multiply parentheses
58t-(3/4(-8t+24))+116=0
We multiply all the terms by the denominator
58t*4(-8t+24))-(3+116*4(-8t+24))=0
Wy multiply elements
232t^2(-+464t(-=0
We use the square of the difference formula
232t^2(-464t(-=0
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