29(8t)=39(11t)

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Solution for 29(8t)=39(11t) equation: 



29(8t)=39(11t)

We move all terms to the left:

29(8t)-(39(11t))=0

determiningTheFunctionDomain
298t-3911t=0

We add all the numbers together, and all the variables

-3613t=0

t=0/-3613

t=0

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