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29(n+3)=4(15+5n)
We move all terms to the left:
29(n+3)-(4(15+5n))=0
We add all the numbers together, and all the variables
29(n+3)-(4(5n+15))=0
We multiply parentheses
29n-(4(5n+15))+87=0
We calculate terms in parentheses: -(4(5n+15)), so:We get rid of parentheses
4(5n+15)
We multiply parentheses
20n+60
Back to the equation:
-(20n+60)
29n-20n-60+87=0
We add all the numbers together, and all the variables
9n+27=0
We move all terms containing n to the left, all other terms to the right
9n=-27
n=-27/9
n=-3
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