29(u+1)=812

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Solution for 29(u+1)=812 equation:



29(u+1)=812
We move all terms to the left:
29(u+1)-(812)=0
We multiply parentheses
29u+29-812=0
We add all the numbers together, and all the variables
29u-783=0
We move all terms containing u to the left, all other terms to the right
29u=783
u=783/29
u=27

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