29+(3y-10)=17

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Solution for 29+(3y-10)=17 equation: 



29+(3y-10)=17

We move all terms to the left:

29+(3y-10)-(17)=0

We add all the numbers together, and all the variables

(3y-10)+12=0

We get rid of parentheses

3y-10+12=0

We add all the numbers together, and all the variables

3y+2=0

We move all terms containing y to the left, all other terms to the right

3y=-2

y=-2/3

y=-2/3

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