29+2x=3(-x+5)-26

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Solution for 29+2x=3(-x+5)-26 equation:



29+2x=3(-x+5)-26
We move all terms to the left:
29+2x-(3(-x+5)-26)=0
We add all the numbers together, and all the variables
2x-(3(-1x+5)-26)+29=0
We calculate terms in parentheses: -(3(-1x+5)-26), so:
3(-1x+5)-26
We multiply parentheses
-3x+15-26
We add all the numbers together, and all the variables
-3x-11
Back to the equation:
-(-3x-11)
We get rid of parentheses
2x+3x+11+29=0
We add all the numbers together, and all the variables
5x+40=0
We move all terms containing x to the left, all other terms to the right
5x=-40
x=-40/5
x=-8

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