29+3y-11=12y-10-2y

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Solution for 29+3y-11=12y-10-2y equation: 



29+3y-11=12y-10-2y

We move all terms to the left:

29+3y-11-(12y-10-2y)=0

We add all the numbers together, and all the variables

3y-(10y-10)+29-11=0

We add all the numbers together, and all the variables

3y-(10y-10)+18=0

We get rid of parentheses

3y-10y+10+18=0

We add all the numbers together, and all the variables

-7y+28=0

We move all terms containing y to the left, all other terms to the right

-7y=-28

y=-28/-7

y=+4

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