29-(2c+3)=2(c+3)+c=

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Solution for 29-(2c+3)=2(c+3)+c= equation: 



29-(2c+3)=2(c+3)+c=

We move all terms to the left:

29-(2c+3)-(2(c+3)+c)=0

We get rid of parentheses

-2c-(2(c+3)+c)-3+29=0



We calculate terms in parentheses: -(2(c+3)+c), so:

2(c+3)+c

We add all the numbers together, and all the variables

c+2(c+3)

We multiply parentheses

c+2c+6

We add all the numbers together, and all the variables

3c+6

Back to the equation:

-(3c+6)



We add all the numbers together, and all the variables

-2c-(3c+6)+26=0

We get rid of parentheses

-2c-3c-6+26=0

We add all the numbers together, and all the variables

-5c+20=0

We move all terms containing c to the left, all other terms to the right

-5c=-20

c=-20/-5

c=+4

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