29-4z=3(z-2)

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Solution for 29-4z=3(z-2) equation: 



29-4z=3(z-2)

We move all terms to the left:

29-4z-(3(z-2))=0



We calculate terms in parentheses: -(3(z-2)), so:

3(z-2)

We multiply parentheses

3z-6

Back to the equation:

-(3z-6)



We get rid of parentheses

-4z-3z+6+29=0

We add all the numbers together, and all the variables

-7z+35=0

We move all terms containing z to the left, all other terms to the right

-7z=-35

z=-35/-7

z=+5

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