29-5=2+3(x+3)

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Solution for 29-5=2+3(x+3) equation:



29-5=2+3(x+3)
We move all terms to the left:
29-5-(2+3(x+3))=0
We add all the numbers together, and all the variables
-(2+3(x+3))+24=0
We calculate terms in parentheses: -(2+3(x+3)), so:
2+3(x+3)
determiningTheFunctionDomain 3(x+3)+2
We multiply parentheses
3x+9+2
We add all the numbers together, and all the variables
3x+11
Back to the equation:
-(3x+11)
We get rid of parentheses
-3x-11+24=0
We add all the numbers together, and all the variables
-3x+13=0
We move all terms containing x to the left, all other terms to the right
-3x=-13
x=-13/-3
x=4+1/3

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