29-n=4(n-2)

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Solution for 29-n=4(n-2) equation: 



29-n=4(n-2)

We move all terms to the left:

29-n-(4(n-2))=0

We add all the numbers together, and all the variables

-1n-(4(n-2))+29=0



We calculate terms in parentheses: -(4(n-2)), so:

4(n-2)

We multiply parentheses

4n-8

Back to the equation:

-(4n-8)



We get rid of parentheses

-1n-4n+8+29=0

We add all the numbers together, and all the variables

-5n+37=0

We move all terms containing n to the left, all other terms to the right

-5n=-37

n=-37/-5

n=7+2/5

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