If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(29/9)*(x-5) = 0
29/9*(x-5) = 0
( 29/9 )
29/9 = 0
x belongs to the empty set
( x-5 )
x-5 = 0 // + 5
x = 5
x = 5
| y-9=(29/9)x(x-5) | | -2/7-1/3 | | y=-10+5x | | X*.4=1500 | | 3x[40x]= | | (23/6)(x-4) | | 3x[3+2x(10-2)]= | | (4+z)(5z-2)=0 | | 9x+3-5x-3-12=0 | | 2x+3(-x)+4=2(-x)+1 | | 5/u-7=3 | | 2x^2-3=-6x-1 | | 6y+7=7y | | 3x-0.3=4x | | -18=a-(-19) | | 2.1+0.5x=0.8x-4.8 | | (3)ln(2)+ln(8)=(2)ln(4x) | | r-2.3=-8.4 | | -2x+(12-9)=11+2x | | x+4(-2)=-2 | | 8.50a+3.50(2a)=279 | | -6(x+4)-42=5-29 | | 7x-5y=-27 | | (4x+1)+(2x+3)= | | 104+9=-45 | | 5y/7=35 | | 14/5=7y | | -4M+4=40 | | x+34=18 | | P+.05p=25.20 | | -16x+4y=20 | | 17+60y+3=100 |