290=((X+1)*2)+(x*25)

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Solution for 290=((X+1)*2)+(x*25) equation: 



290=((X+1)*2)+(X*25)

We move all terms to the left:

290-(((X+1)*2)+(X*25))=0

We add all the numbers together, and all the variables

-(((X+1)*2)+(+X*25))+290=0



We calculate terms in parentheses: -(((X+1)*2)+(+X*25)), so:

((X+1)*2)+(+X*25)

We get rid of parentheses

((X+1)*2)+X*25



We calculate terms in parentheses: +((X+1)*2), so:

(X+1)*2

We multiply parentheses

2X+2

Back to the equation:

+(2X+2)



Wy multiply elements

(2X+2)+25X

We get rid of parentheses

2X+25X+2

We add all the numbers together, and all the variables

27X+2

Back to the equation:

-(27X+2)



We get rid of parentheses

-27X-2+290=0

We add all the numbers together, and all the variables

-27X+288=0

We move all terms containing X to the left, all other terms to the right

-27X=-288

X=-288/-27

X=10+2/3

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