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294-9/8x=5x
We move all terms to the left:
294-9/8x-(5x)=0
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
-5x-9/8x+294=0
We multiply all the terms by the denominator
-5x*8x+294*8x-9=0
Wy multiply elements
-40x^2+2352x-9=0
a = -40; b = 2352; c = -9;
Δ = b2-4ac
Δ = 23522-4·(-40)·(-9)
Δ = 5530464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5530464}=\sqrt{144*38406}=\sqrt{144}*\sqrt{38406}=12\sqrt{38406}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2352)-12\sqrt{38406}}{2*-40}=\frac{-2352-12\sqrt{38406}}{-80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2352)+12\sqrt{38406}}{2*-40}=\frac{-2352+12\sqrt{38406}}{-80} $
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