296=(x-40)(x-44)

Solution for 296=(x-40)(x-44) equation:

296=(x-40)(x-44)

We move all terms to the left:

296-((x-40)(x-44))=0

We multiply parentheses ..

-((+x^2-44x-40x+1760))+296=0


We calculate terms in parentheses: -((+x^2-44x-40x+1760)), so:

(+x^2-44x-40x+1760)

We get rid of parentheses

x^2-44x-40x+1760

We add all the numbers together, and all the variables

x^2-84x+1760

Back to the equation:

-(x^2-84x+1760)


We get rid of parentheses

-x^2+84x-1760+296=0

We add all the numbers together, and all the variables

-1x^2+84x-1464=0

a = -1; b = 84; c = -1464;
Δ = b2-4ac
Δ = 842-4·(-1)·(-1464)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-20\sqrt{3}}{2*-1}=\frac{-84-20\sqrt{3}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+20\sqrt{3}}{2*-1}=\frac{-84+20\sqrt{3}}{-2}
$