29=(2x+x)+2x+(3-2)

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Solution for 29=(2x+x)+2x+(3-2) equation: 



29=(2x+x)+2x+(3-2)

We move all terms to the left:

29-((2x+x)+2x+(3-2))=0

We add all the numbers together, and all the variables

-((+3x)+2x+1)+29=0



We calculate terms in parentheses: -((+3x)+2x+1), so:

(+3x)+2x+1

We add all the numbers together, and all the variables

2x+(+3x)+1

We get rid of parentheses

2x+3x+1

We add all the numbers together, and all the variables

5x+1

Back to the equation:

-(5x+1)



We get rid of parentheses

-5x-1+29=0

We add all the numbers together, and all the variables

-5x+28=0

We move all terms containing x to the left, all other terms to the right

-5x=-28

x=-28/-5

x=5+3/5

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