29=-3+5(r-5)

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Solution for 29=-3+5(r-5) equation: 



29=-3+5(r-5)

We move all terms to the left:

29-(-3+5(r-5))=0



We calculate terms in parentheses: -(-3+5(r-5)), so:

-3+5(r-5)

determiningTheFunctionDomain
5(r-5)-3

We multiply parentheses

5r-25-3

We add all the numbers together, and all the variables

5r-28

Back to the equation:

-(5r-28)



We get rid of parentheses

-5r+28+29=0

We add all the numbers together, and all the variables

-5r+57=0

We move all terms containing r to the left, all other terms to the right

-5r=-57

r=-57/-5

r=11+2/5

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