29=15-(2z-3)

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Solution for 29=15-(2z-3) equation: 



29=15-(2z-3)

We move all terms to the left:

29-(15-(2z-3))=0



We calculate terms in parentheses: -(15-(2z-3)), so:

15-(2z-3)

determiningTheFunctionDomain
-(2z-3)+15

We get rid of parentheses

-2z+3+15

We add all the numbers together, and all the variables

-2z+18

Back to the equation:

-(-2z+18)



We get rid of parentheses

2z-18+29=0

We add all the numbers together, and all the variables

2z+11=0

We move all terms containing z to the left, all other terms to the right

2z=-11

z=-11/2

z=-5+1/2

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