29=2(2z+3)-4(2z-6)-13

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Solution for 29=2(2z+3)-4(2z-6)-13 equation:


Simplifying
29 = 2(2z + 3) + -4(2z + -6) + -13

Reorder the terms:
29 = 2(3 + 2z) + -4(2z + -6) + -13
29 = (3 * 2 + 2z * 2) + -4(2z + -6) + -13
29 = (6 + 4z) + -4(2z + -6) + -13

Reorder the terms:
29 = 6 + 4z + -4(-6 + 2z) + -13
29 = 6 + 4z + (-6 * -4 + 2z * -4) + -13
29 = 6 + 4z + (24 + -8z) + -13

Reorder the terms:
29 = 6 + 24 + -13 + 4z + -8z

Combine like terms: 6 + 24 = 30
29 = 30 + -13 + 4z + -8z

Combine like terms: 30 + -13 = 17
29 = 17 + 4z + -8z

Combine like terms: 4z + -8z = -4z
29 = 17 + -4z

Solving
29 = 17 + -4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '4z' to each side of the equation.
29 + 4z = 17 + -4z + 4z

Combine like terms: -4z + 4z = 0
29 + 4z = 17 + 0
29 + 4z = 17

Add '-29' to each side of the equation.
29 + -29 + 4z = 17 + -29

Combine like terms: 29 + -29 = 0
0 + 4z = 17 + -29
4z = 17 + -29

Combine like terms: 17 + -29 = -12
4z = -12

Divide each side by '4'.
z = -3

Simplifying
z = -3

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