29=3(u-2)+4u

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Solution for 29=3(u-2)+4u equation: 



29=3(u-2)+4u

We move all terms to the left:

29-(3(u-2)+4u)=0



We calculate terms in parentheses: -(3(u-2)+4u), so:

3(u-2)+4u

We add all the numbers together, and all the variables

4u+3(u-2)

We multiply parentheses

4u+3u-6

We add all the numbers together, and all the variables

7u-6

Back to the equation:

-(7u-6)



We get rid of parentheses

-7u+6+29=0

We add all the numbers together, and all the variables

-7u+35=0

We move all terms containing u to the left, all other terms to the right

-7u=-35

u=-35/-7

u=+5

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