29=3c-(6-2c)

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Solution for 29=3c-(6-2c) equation: 



29=3c-(6-2c)

We move all terms to the left:

29-(3c-(6-2c))=0

We add all the numbers together, and all the variables

-(3c-(-2c+6))+29=0



We calculate terms in parentheses: -(3c-(-2c+6)), so:

3c-(-2c+6)

We get rid of parentheses

3c+2c-6

We add all the numbers together, and all the variables

5c-6

Back to the equation:

-(5c-6)



We get rid of parentheses

-5c+6+29=0

We add all the numbers together, and all the variables

-5c+35=0

We move all terms containing c to the left, all other terms to the right

-5c=-35

c=-35/-5

c=+7

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