29=4(4x-5)+1

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Solution for 29=4(4x-5)+1 equation: 



29=4(4x-5)+1

We move all terms to the left:

29-(4(4x-5)+1)=0



We calculate terms in parentheses: -(4(4x-5)+1), so:

4(4x-5)+1

We multiply parentheses

16x-20+1

We add all the numbers together, and all the variables

16x-19

Back to the equation:

-(16x-19)



We get rid of parentheses

-16x+19+29=0

We add all the numbers together, and all the variables

-16x+48=0

We move all terms containing x to the left, all other terms to the right

-16x=-48

x=-48/-16

x=+3

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