29x-2-5x(2x-4)=4x(1-8x)-37

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Solution for 29x-2-5x(2x-4)=4x(1-8x)-37 equation: 



29x-2-5x(2x-4)=4x(1-8x)-37

We move all terms to the left:

29x-2-5x(2x-4)-(4x(1-8x)-37)=0

We add all the numbers together, and all the variables

29x-5x(2x-4)-(4x(-8x+1)-37)-2=0

We multiply parentheses

-10x^2+29x+20x-(4x(-8x+1)-37)-2=0



We calculate terms in parentheses: -(4x(-8x+1)-37), so:

4x(-8x+1)-37

We multiply parentheses

-32x^2+4x-37

Back to the equation:

-(-32x^2+4x-37)



We add all the numbers together, and all the variables

-10x^2-(-32x^2+4x-37)+49x-2=0

We get rid of parentheses

-10x^2+32x^2-4x+49x+37-2=0

We add all the numbers together, and all the variables

22x^2+45x+35=0

a = 22; b = 45; c = +35;
Δ = b2-4ac
Δ = 452-4·22·35
Δ = -1055
Delta is less than zero, so there is no solution for the equation

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