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29y-4(6y-5)=3y-3+2y
We move all terms to the left:
29y-4(6y-5)-(3y-3+2y)=0
We add all the numbers together, and all the variables
29y-4(6y-5)-(5y-3)=0
We multiply parentheses
29y-24y-(5y-3)+20=0
We get rid of parentheses
29y-24y-5y+3+20=0
We add all the numbers together, and all the variables
23!=0
There is no solution for this equation
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