2;1/2q+1)=-3(2q-1)+4(2q+1)

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Solution for 2;1/2q+1)=-3(2q-1)+4(2q+1) equation: 



21/2q+1)=-3(2q-1)+4(2q+1)

We move all terms to the left:

21/2q+1)-(-3(2q-1)+4(2q+1))=0



Domain of the equation: 2q!=0

q!=0/2

q!=0

q∈R



We multiply parentheses

21/2q-6q+4(2q+1))+1)-(+3=0

We multiply all the terms by the denominator


-6q*2q+(4(2q+1))+3)*2q+21+1)-(=0



We calculate terms in parentheses: +(4(2q+1)), so:

4(2q+1)

We multiply parentheses

8q+4

Back to the equation:

+(8q+4)



Wy multiply elements

-12q^2+(8q+4)+3)*2q+21+1)-(=0

We get rid of parentheses

-12q^2+8q+3)*2q+21+1)-(+4=0

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