2=((1-a)/(a-4))/(a-2)

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Solution for 2=((1-a)/(a-4))/(a-2) equation:


D( a )

a-4 = 0

a-2 = 0

a-4 = 0

a-4 = 0

a-4 = 0 // + 4

a = 4

a-2 = 0

a-2 = 0

a-2 = 0 // + 2

a = 2

a in (-oo:2) U (2:4) U (4:+oo)

2 = ((1-a)/(a-4))/(a-2) // - ((1-a)/(a-4))/(a-2)

2-(((1-a)/(a-4))/(a-2)) = 0

(-1*(1-a))/((a-4)*(a-2))+2 = 0

(-1*(1-a))/((a-4)*(a-2))+(2*(a-4)*(a-2))/((a-4)*(a-2)) = 0

2*(a-4)*(a-2)-1*(1-a) = 0

2*a^2-11*a+15 = 0

2*a^2-11*a+15 = 0

2*a^2-11*a+15 = 0

DELTA = (-11)^2-(2*4*15)

DELTA = 1

DELTA > 0

a = (1^(1/2)+11)/(2*2) or a = (11-1^(1/2))/(2*2)

a = 3 or a = 5/2

(a-5/2)*(a-3) = 0

((a-5/2)*(a-3))/((a-4)*(a-2)) = 0

((a-5/2)*(a-3))/((a-4)*(a-2)) = 0 // * (a-4)*(a-2)

(a-5/2)*(a-3) = 0

( a-3 )

a-3 = 0 // + 3

a = 3

( a-5/2 )

a-5/2 = 0 // + 5/2

a = 5/2

a in { 3, 5/2 }

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