2=((4-(2r))/3)

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Solution for 2=((4-(2r))/3) equation: 


r in (-oo:+oo)

2 <= (4-(2*r))/3 // - (4-(2*r))/3

2-((4-(2*r))/3) <= 0

2-((4-2*r)/3) <= 0

(-1*(4-2*r))/3+2 <= 0

(-1*(4-2*r))/3+(2*3)/3 <= 0

2*3-1*(4-2*r) <= 0

2*r+2 <= 0

(2*r+2)/3 <= 0

(2*r+2)/3 <= 0 // * 3^2

3*(2*r+2) <= 0

( 2*r+2 )

2*r+2 <= 0 // - 2

2*r <= -2 // : 2

r <= -2/2

r <= -1

( 3 )

3 <= 0

r belongs to the empty set

	(-oo:-1)	(-1:+oo)
2*r+2	-	+
3	+	+


r in (-oo:-1>

(-oo:-1>

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