2=(0.4)(x-3)(x-3)+1.2

Solution for 2=(0.4)(x-3)(x-3)+1.2 equation:

2=(0.4)(x-3)(x-3)+1.2

We move all terms to the left:

2-((0.4)(x-3)(x-3)+1.2)=0

We multiply parentheses ..

-((+0.4x-1.2)(x-3)+1.2)+2=0


We calculate terms in parentheses: -((+0.4x-1.2)(x-3)+1.2), so:

(+0.4x-1.2)(x-3)+1.2

We add all the numbers together, and all the variables

(0.4x-1.2)(x-3)+1.2

We multiply parentheses ..

(+0x^2+0x-1.2x+3.6)+1.2

We get rid of parentheses

0x^2+0x-1.2x+3.6+1.2

We add all the numbers together, and all the variables

x^2-0.2x+4.8

Back to the equation:

-(x^2-0.2x+4.8)


We get rid of parentheses

-x^2+0.2x-4.8+2=0

We add all the numbers together, and all the variables

-1x^2+0.2x-2.8=0

a = -1; b = 0.2; c = -2.8;
Δ = b2-4ac
Δ = 0.22-4·(-1)·(-2.8)
Δ = -11.16
Delta is less than zero, so there is no solution for the equation