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2=(1/2)x+2
We move all terms to the left:
2-((1/2)x+2)=0
Domain of the equation: 2)x+2)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-((+1/2)x+2)+2=0
We multiply all the terms by the denominator
-((+1+2*2)x+2)=0
We calculate terms in parentheses: -((+1+2*2)x+2), so:We get rid of parentheses
(+1+2*2)x+2
We add all the numbers together, and all the variables
5x+2
Back to the equation:
-(5x+2)
-5x-2=0
We move all terms containing x to the left, all other terms to the right
-5x=2
x=2/-5
x=-2/5
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