2=(1/4)3+b

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Solution for 2=(1/4)3+b equation: 



2=(1/4)3+b

We move all terms to the left:

2-((1/4)3+b)=0



Domain of the equation: 4)3+b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

-((+1/4)3+b)+2=0

We multiply all the terms by the denominator


-((+1+2*4)3+b)=0



We calculate terms in parentheses: -((+1+2*4)3+b), so:

(+1+2*4)3+b

determiningTheFunctionDomain
b+(+1+2*4)3

We add all the numbers together, and all the variables

b+93

Back to the equation:

-(b+93)



We get rid of parentheses

-b-93=0

We add all the numbers together, and all the variables

-1b-93=0

We move all terms containing b to the left, all other terms to the right

-b=93

b=93/-1

b=-93

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