2=(1/5)x+3

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Solution for 2=(1/5)x+3 equation: 



2=(1/5)x+3

We move all terms to the left:

2-((1/5)x+3)=0



Domain of the equation: 5)x+3)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+1/5)x+3)+2=0

We multiply all the terms by the denominator


-((+1+2*5)x+3)=0



We calculate terms in parentheses: -((+1+2*5)x+3), so:

(+1+2*5)x+3

We add all the numbers together, and all the variables

11x+3

Back to the equation:

-(11x+3)



We get rid of parentheses

-11x-3=0

We move all terms containing x to the left, all other terms to the right

-11x=3

x=3/-11

x=-3/11

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