2=(1/6)(10x+6)

Solution for 2=(1/6)(10x+6) equation:

2=(1/6)(10x+6)

We move all terms to the left:

2-((1/6)(10x+6))=0


Domain of the equation: 6)(10x+6))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/6)(10x+6))+2=0

We multiply parentheses ..

-((+10x^2+1/6*6))+2=0

We multiply all the terms by the denominator


-((+10x^2+1+2*6*6))=0


We calculate terms in parentheses: -((+10x^2+1+2*6*6)), so:

(+10x^2+1+2*6*6)

We get rid of parentheses

10x^2+1+2*6*6

We add all the numbers together, and all the variables

10x^2+73

Back to the equation:

-(10x^2+73)


We get rid of parentheses

-10x^2-73=0

a = -10; b = 0; c = -73;
Δ = b2-4ac
Δ = 02-4·(-10)·(-73)
Δ = -2920
Delta is less than zero, so there is no solution for the equation