2=(6/5)(5)+b

Solution for 2=(6/5)(5)+b equation:

2=(6/5)(5)+b

We move all terms to the left:

2-((6/5)(5)+b)=0


Domain of the equation: 5)5+b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

-((+6/5)5+b)+2=0

We multiply all the terms by the denominator


-((+6+2*5)5+b)=0


We calculate terms in parentheses: -((+6+2*5)5+b), so:

(+6+2*5)5+b

determiningTheFunctionDomain
b+(+6+2*5)5

We add all the numbers together, and all the variables

b+165

Back to the equation:

-(b+165)


We get rid of parentheses

-b-165=0

We add all the numbers together, and all the variables

-1b-165=0

We move all terms containing b to the left, all other terms to the right

-b=165

b=165/-1

b=-165