2=(k/3)-2

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Solution for 2=(k/3)-2 equation:



2=(k/3)-2
We move all terms to the left:
2-((k/3)-2)=0
We add all the numbers together, and all the variables
-((+k/3)-2)+2=0
We multiply all the terms by the denominator
-((+k+2*3)-2)=0
We calculate terms in parentheses: -((+k+2*3)-2), so:
(+k+2*3)-2
We add all the numbers together, and all the variables
(k+6)-2
We get rid of parentheses
k+6-2
We add all the numbers together, and all the variables
k+4
Back to the equation:
-(k+4)
We get rid of parentheses
-k-4=0
We add all the numbers together, and all the variables
-1k-4=0
We move all terms containing k to the left, all other terms to the right
-k=4
k=4/-1
k=-4

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