2=(x+3)/10

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Solution for 2=(x+3)/10 equation: 



2=(x+3)/10

We move all terms to the left:

2-((x+3)/10)=0

We multiply all the terms by the denominator


-((x+3)+2*10)=0



We calculate terms in parentheses: -((x+3)+2*10), so:

(x+3)+2*10

We add all the numbers together, and all the variables

(x+3)+20

We get rid of parentheses

x+3+20

We add all the numbers together, and all the variables

x+23

Back to the equation:

-(x+23)



We get rid of parentheses

-x-23=0

We add all the numbers together, and all the variables

-1x-23=0

We move all terms containing x to the left, all other terms to the right

-x=23

x=23/-1

x=-23

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