2=(z-2)/2

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Solution for 2=(z-2)/2 equation: 



2=(z-2)/2

We move all terms to the left:

2-((z-2)/2)=0

We multiply all the terms by the denominator


-((z-2)+2*2)=0



We calculate terms in parentheses: -((z-2)+2*2), so:

(z-2)+2*2

We add all the numbers together, and all the variables

(z-2)+4

We get rid of parentheses

z-2+4

We add all the numbers together, and all the variables

z+2

Back to the equation:

-(z+2)



We get rid of parentheses

-z-2=0

We add all the numbers together, and all the variables

-1z-2=0

We move all terms containing z to the left, all other terms to the right

-z=2

z=2/-1

z=-2

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