2=-(v+5)+-8(1-2v)

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Solution for 2=-(v+5)+-8(1-2v) equation: 



2=-(v+5)+-8(1-2v)

We move all terms to the left:

2-(-(v+5)+-8(1-2v))=0

We add all the numbers together, and all the variables

-(-(v+5)+-8(-2v+1))+2=0

We use the square of the difference formula

-(-(v+5)-8(-2v+1))+2=0



We calculate terms in parentheses: -(-(v+5)-8(-2v+1)), so:

-(v+5)-8(-2v+1)

We multiply parentheses

-(v+5)+16v-8

We get rid of parentheses

-v+16v-5-8

We add all the numbers together, and all the variables

15v-13

Back to the equation:

-(15v-13)



We get rid of parentheses

-15v+13+2=0

We add all the numbers together, and all the variables

-15v+15=0

We move all terms containing v to the left, all other terms to the right

-15v=-15

v=-15/-15

v=1

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