2=-2(-2c+6)-3c

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Solution for 2=-2(-2c+6)-3c equation:



2=-2(-2c+6)-3c
We move all terms to the left:
2-(-2(-2c+6)-3c)=0
We calculate terms in parentheses: -(-2(-2c+6)-3c), so:
-2(-2c+6)-3c
We add all the numbers together, and all the variables
-3c-2(-2c+6)
We multiply parentheses
-3c+4c-12
We add all the numbers together, and all the variables
c-12
Back to the equation:
-(c-12)
We get rid of parentheses
-c+12+2=0
We add all the numbers together, and all the variables
-1c+14=0
We move all terms containing c to the left, all other terms to the right
-c=-14
c=-14/-1
c=+14

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